feat(brain): Knapsack DP replacement for optimal bar nesting

src/main.js

@@ -495,14 +495,13 @@ function showFeedback(message, type) {
     showToast(message, type);
 }
 
-// ===== ALGORITMO FFD AVANÇADO =====
+// ===== ALGORITMO OTIMIZADO AVANÇADO (Programação Dinâmica / Knapsack) =====
 function optimizeCutting() {
     if (availableBars.length === 0 || demandPieces.length === 0) {
-        showToast('Adicione barras e peças', 'warning');
+        showToast("Adicione barras e peças", "warning");
         return;
     }
 
-    // Expandir peças com ID único global
     const expandedPieces = [];
     let uniqueIdCounter = 0;
     demandPieces.forEach(p => {
@@ -511,14 +510,12 @@ function optimizeCutting() {
         }
     });
 
-    // FFD em cada barra disponível
     const usedBars = [];
-    const unusedPieces = [...expandedPieces];
+    let unusedPieces = [...expandedPieces];
 
-    // Ordenar barras por comprimento (maior para menor) para tentar usar as maiores primeiro?
+    const sortedBarTypes = [...availableBars].sort((a, b) => b.length - a.length);
-    // O código original não ordenava, seguia a ordem de inserção. Manteremos assim por enquanto.
 
-    for (let barType of availableBars) {
+    for (let barType of sortedBarTypes) {
         for (let barCopy = 0; barCopy < barType.qty; barCopy++) {
             if (unusedPieces.length === 0) break;
 
@@ -531,48 +528,47 @@ function optimizeCutting() {
                 isSimulated: barType.isSimulated || false
             };
 
-            // Tentar encaixar peças (FFD)
+            unusedPieces.sort((a, b) => b.length - a.length);
-            // Ordenar peças restantes por tamanho decrescente
-            const sorted = [...unusedPieces].sort((a, b) => b.length - a.length);
-            const toRemoveIds = [];
             
-            for (let piece of sorted) {
+            const N = unusedPieces.length;
-                // Check if piece fits considering kerf loss for this cut
+            const capacity = bar.remaining;
-                // We assume each piece consumes its length + kerf
-                // Exception: The very last piece in a bar might not strictly need a kerf if it's the end,
-                // but usually in cutting processes, you cut the piece out, so kerf is consumed.
-                // User requirement: "consumo adicional de cada corte... sera de mais 2mm para cada corte"
             
-                const requiredSpace = piece.length + kerfSize;
+            const dp = new Int32Array(capacity + 1);
+            const keep = new Array(N);
 
-                // However, we need to be careful. If remaining is EXACTLY piece.length, can we cut it?
+            for (let i = 0; i < N; i++) {
-                // If we cut it, we lose the kerf. So we need remaining >= piece.length + kerf?
+                keep[i] = new Uint8Array(capacity + 1);
-                // Or does the kerf come from the "waste"?
+                const w = unusedPieces[i].length + kerfSize;
-                // Usually: Bar 6000. Piece 1000. Kerf 3.
-                // Cut 1: Consumes 1003. Remaining 4997.
-                // So yes, we treat piece length as (length + kerf).
                 
-                if (bar.remaining >= requiredSpace) {
+                for (let j = capacity; j >= 0; j--) {
-                    bar.pieces.push(piece);
+                    if (j >= w && dp[j - w] + w > dp[j]) {
-                    bar.remaining -= requiredSpace;
+                        dp[j] = dp[j - w] + w;
-                    toRemoveIds.push(piece.uniqueId);
+                        keep[i][j] = 1;
-                } else if (bar.remaining >= piece.length && bar.remaining < requiredSpace) {
+                    }
-                    // Edge case: Fits exactly or with less than kerf remaining?
-                    // If I have 1000mm remaining and need 1000mm piece.
-                    // If I cut, I destroy 3mm. So I need 1003mm to get a 1000mm piece?
-                    // Yes, usually. Unless it's the raw end of the bar, but we can't assume that.
-                    // Let's stick to the rule: consumption = length + kerf.
-                    // If bar.remaining < length + kerf, we can't cut it.
                 }
             }
 
-            // Remover peças colocadas usando ID único
+            let bestW = 0;
-            for (let uid of toRemoveIds) {
+            for(let j = 0; j <= capacity; j++) {
-                const idx = unusedPieces.findIndex(p => p.uniqueId === uid);
+                if(dp[j] > dp[bestW]) bestW = j;
-                if (idx !== -1) unusedPieces.splice(idx, 1);
+            }
+            let currW = bestW;
+            
+            const toRemoveIds = [];
+            for (let i = N - 1; i >= 0; i--) {
+                if (keep[i][currW] === 1) {
+                    const selectedPiece = unusedPieces[i];
+                    bar.pieces.push(selectedPiece);
+                    const w = selectedPiece.length + kerfSize;
+                    bar.remaining -= w;
+                    currW -= w;
+                    toRemoveIds.push(selectedPiece.uniqueId);
+                }
             }
 
-            if (bar.pieces.length > 0) {
+            if (toRemoveIds.length > 0) {
+                const removeSet = new Set(toRemoveIds);
+                unusedPieces = unusedPieces.filter(p => !removeSet.has(p.uniqueId));
                 usedBars.push(bar);
             }
         }